凸轮分割器之输送带式传动 |
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点击这返回总目录 |
注意:绿色的框内请根据工况修改,粉红色的框内为建议值,可改可不改。橘色的为自动计算值,不得更改! |
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工况 |
代号 |
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单位 |
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参数输入区 |
间歇分割等份 |
N |
= |
6.0 |
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直接结果 |
选择的实际负载Te要大于 |
12.01 |
kg. m |
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主动齿轮节圆直径 |
D1 |
= |
20 |
cm |
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主动齿轮重量 |
W1 |
= |
5 |
kg |
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需要电机功率要大于 |
0.34 |
kw |
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从动齿轮节圆直径 |
D2 |
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20 |
cm |
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从动齿轮重量 |
W2 |
= |
5 |
kg |
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摩擦扭矩 |
271.78 |
HP |
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传动轴直径 |
D3 |
= |
6 |
cm |
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传动轴重量 |
W3 |
= |
5 |
kg |
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静扭矩(惯性扭矩) |
328.90 |
kg.m |
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传动轴数量 |
A3 |
= |
2 |
支 |
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链轮节圆直径 |
D4 |
= |
48.533 |
cm |
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链轮重量 |
W4 |
= |
15 |
kg(每组) |
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链轮组数 |
A4 |
= |
4 |
组 |
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链条重量 |
W5 |
= |
10 |
kg(每条) |
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链条数量 |
A5 |
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2 |
条 |
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夹具重量 |
W6 |
= |
2 |
kg(每组) |
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夹具组数 |
A6 |
= |
16 |
组 |
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工件重量 |
W7 |
= |
6 |
kg(每组) |
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工件组数 |
A7 |
= |
5 |
组 |
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输送带输送间距 |
Pc |
= |
25.4 |
cm |
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凸轮转位角度 |
Qh |
= |
180 |
度 |
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入力轴回转数 |
n |
= |
50 |
rpm |
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速度比 |
v |
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1 |
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凸轮曲线系修正正弦曲线(M.S.),因此: |
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最大非向性速度 |
Vm |
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1.76 |
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最大非向性加速度 |
Am |
= |
5.53 |
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凸轮最大扭力系数 |
Qm |
= |
0.99 |
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摩擦系数 |
u |
= |
0.2 |
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安全系数 |
fe |
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2 |
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马达效率 |
Z |
= |
0.7 |
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以下为自动计算过程(请勿修改): |
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(一).负载扭矩(Tt): |
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(1).惯性扭矩(Ti): |
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(a).主动齿轮惯性扭矩IA |
= |
((W1*R1^2)/2G) |
= |
0.00255102 |
(kg.m.S2) |
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(b.)输送带之总惯性矩……..(IB) |
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(1).从动齿轮惯性矩(I2) |
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= |
((W2*((R2^2)+(R3^2)))/(2*G)) |
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= |
0.002780612 |
(kg.m.S2) |
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(2).传动轴之惯性矩(I3) |
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= |
((W3*(R3^2))/(2*G))*A3 |
= |
0.000459184 |
(kg.m.S2) |
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(3).链轮之惯性矩(I4) |
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= |
((W4*((R4^2)+(R3^2)))/(2*G))*A4 |
= |
0.183019293 |
(kg.m.S2) |
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(4).链条之惯性矩(I5) |
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= |
((W5*(R4^2))/G)*A5 |
= |
0.120176127 |
(kg.m.S2) |
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(5).夹具之惯性矩(I6) |
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((W6*(R4^2))/G)*A6 |
= |
0.192281803 |
(kg.m.S2) |
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(6).工件之惯性矩(I7) |
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= |
((W7*(R4^2))/G)*A7 |
= |
0.18026419 |
(kg.m.S2) |
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(b.)输送带之总惯性矩(IB) |
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= |
I2+I3+I4+I5+I6+I7 |
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= |
0.678981209 |
(kg.m.S2) |
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(c.)输送带之有效总惯性矩.(IC) |
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(IB*((D1/D2)^2)) |
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= |
0.678981209 |
(kg.m.S2) |
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(d.)总惯性矩为(a)+(b)之和I |
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IA+IC |
= |
0.68153223 |
(kg.m.S2) |
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(e.)出力轴最大角加速度(O) |
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= |
Am*(2π/N)*(((360/Qh)*((n/2)/60))^2) |
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= |
4.825835299 |
(rad .S^2) |
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(f.)静扭矩(惯性扭矩)(Ti) |
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= |
I*O |
= |
328.8962291 |
(kg . cm) |
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(2).摩擦扭矩 |
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(a.)输送带上之摩擦扭矩.(Tf) |
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= |
u * w * R |
= |
271.7848 |
(kg . cm) |
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摩擦负荷应等于滑动面上链条和夹具的一半重量和工件全部重量所造成之摩擦力 |
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(b.)输送带之有效摩擦扭矩(Tfe) |
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Tf*(D1/D2) |
= |
271.7848 |
(kg . cm) |
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(3).作功扭矩(Tw) 在间歇分割时没有作功,因此 Tw = 0 |
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(4).以上总负载扭矩……...(Tt) |
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= |
Ti + Tf + Tw |
= |
6.006810291 |
(kg . m) |
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(二).实际负载扭矩…...(Te) |
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= |
Tt * fc |
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= |
12.01362058 |
(kg . m) |
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(三).入力轴扭矩(Tc) 注:入力轴起动负载扭矩视为0 , 因此 Tca =0 |
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= |
[360 / (Qh * N)] * Qm * (Te + Tca) |
= |
3.964494792 |
(kg . m) |
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(四).计算所须之马力….(P) |
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( Tc * n ) / (716 * Z) |
= |
0.461416992 |
(HP) |
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或 (P) |
= |
( Tc * n ) / (975 * Z) |
= |
0.338845709 |
(kw) |
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选型案例1(正名分割器) |
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